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//DISABLE_TEST(compute):COMPARE_COMPUTE_EX:-slang -compute -shaderobj
/* A test for equality around interface types
Here again trying to apply equality *outside* of the types (MyStruct) definition.
Doesn't work:
.slang(24): error 30019: expected an expression of type 'Type', got 'T'
return T::isEqual(a, b);
Note! This may be somewhat of a silly example for equality. We could get what we want here by just
implementing 'isEqual(MyStruct a, MyStruct b)` as a free function and use overloading.
*/
//TEST_INPUT:ubuffer(data=[0 0 0 0], stride=4):out,name outputBuffer
RWStructuredBuffer<float> outputBuffer;
struct MyStruct
{
int a = 10;
};
interface IEquality
{
associatedtype Type;
static bool isEqual(Type a, Type b);
}
extension MyStruct : IEquality
{
// Do I need this? Is the type This?
typedef MyStruct Type;
static bool isEqual(Type a, Type b) { return a.a == b.a; }
};
__generic<T : IEquality>
bool isEqual(T a, T b)
{
return T::isEqual(a, b);
}
[numthreads(4, 1, 1)]
void computeMain(uint3 dispatchThreadID : SV_DispatchThreadID)
{
int index = dispatchThreadID.x;
MyStruct a = { 1 };
MyStruct b = { 2 };
bool res = isEqual(a, b);
outputBuffer[index] = 1 + int(res);
}
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