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#!/usr/bin/env python3
# python3 -m pip install editdistance
# License: MIT.
import editdistance
import typing
DEBUG = False
# Find the window where the distance between these two transcriptions is
# minimized and use it to stitch them together.
def matchStringList(old_words: typing.List[str],
new_words: typing.List[str], window_size = 6) -> str:
if old_words == new_words:
return " ".join(old_words)
elif len(old_words) >= window_size and len(new_words) >= window_size:
# Find the window where the cumulative string distance
# between the words in that window in the old/new transcription
# is minimized.
old_slice = old_words[len(old_words) - window_size:]
best_match_i = None
best_match_d = window_size * 1000
for i in range(0, 1 + len(new_words) - window_size):
new_slice = new_words[i:i + window_size]
cur_d = 0
for j in range(0, window_size):
cur_d += editdistance.eval(old_slice[j], new_slice[j])
if cur_d < best_match_d:
best_match_i = i
best_match_d = cur_d
old_prefix = old_words[0:len(old_words) - window_size]
overlap = new_words[best_match_i:best_match_i + window_size]
new_suffix = new_words[best_match_i + window_size:]
#print("Best match i: {}".format(best_match_i))
#print("Window size: {}".format(window_size))
#print("Old prefix: {}".format(old_prefix))
#print("Overlap: {}".format(overlap))
#print("New suffix: {}".format(new_suffix))
return " ".join(old_prefix + new_words[best_match_i:])
else:
return " ".join(new_words)
def matchSpaceDelimitedStrings(old_text: str, new_text: str, window_size = 4) -> str:
old_words = old_text.split()
new_words = new_text.split()
return matchStringList(old_words, new_words, window_size)
def matchStrings(old_text: str, new_text: str, window_size = 3) -> str:
if old_text == new_text:
print("STRING MATCH exception path 1")
return old_text
elif len(old_text) >= window_size and len(new_text) >= window_size:
# Find the window where the cumulative string distance
# between the text in that window in the old/new transcription
# is minimized.
best_match_i = None
best_match_j = None
best_match_d = window_size * 1000
# The number of old slices to look at. Since the old text can grow
# unboundedly, it's crucial that we don't compare to every possible
# slice in the old and new transcriptions (O(N^2) time complexity).
# This is still wildly inefficient, but good enough for continuous
# transcription in a game bound by a single CPU core, like VRChat.
max_old_slices = 150
old_n_slices = min(max_old_slices, len(old_text))
last_old_window = len(old_text) - window_size
first_old_window = max(last_old_window - old_n_slices, 0)
for i in range(first_old_window, last_old_window + 1):
old_slice = old_text[i:i + window_size]
for j in range(0, 1 + len(new_text) - window_size):
new_slice = new_text[j:j + window_size]
cur_d = editdistance.eval(old_slice, new_slice)
if cur_d < best_match_d:
best_match_i = i
best_match_j = j
best_match_d = cur_d
if DEBUG:
print("optimum at old '{}' i={} new '{}' j={} d={}".format(
old_slice, i, new_slice, j, cur_d))
old_prefix = old_text[0:best_match_i]
overlap = new_text[best_match_j:best_match_j + window_size]
new_suffix = new_text[best_match_j + window_size:]
if DEBUG:
print("Best match i: {}".format(best_match_i))
print("Best match j: {}".format(best_match_j))
print("Window size: {}".format(window_size))
print("Old prefix: {}".format(old_prefix))
print("Overlap: {}".format(overlap))
print("New suffix: {}".format(new_suffix))
print("Input 1: {}".format(old_text))
print("Input 2: {}".format(new_text))
print("Output: {}".format(old_prefix +
new_text[best_match_j:]))
return old_prefix + new_text[best_match_j:]
else:
print("STRING MATCH exception path 2")
print(" OLD: {}".format(old_text))
print(" NEW: {}".format(new_text))
return new_text
if __name__ == "__main__":
# Identical transcriptions should not be changed.
assert(matchSpaceDelimitedStrings("This is a test case.", "This is a test case.", window_size = 3) == "This is a test case.")
# A suffix should be detected and ignored.
assert(matchSpaceDelimitedStrings("This is a test case.", "is a test case.", window_size = 3) == "This is a test case.")
# A lengthening suffix should be correctly appended.
assert(matchSpaceDelimitedStrings("This is a test", "is a test case.", window_size = 3) == "This is a test case.")
# A strictly longer transcription should override the old prefix.
assert(matchSpaceDelimitedStrings("This is a test", "This is a test case.", window_size = 3) == "This is a test case.")
# Paranoia: repetitive text broke the older implementation, so I included
# some test cases without fully understanding what the old problem was.
assert(matchSpaceDelimitedStrings("test test test", "test test test test test test", window_size
= 3) == "test test test test test test")
assert(matchSpaceDelimitedStrings("test test test test test test", "test test test", window_size
= 3) == "test test test test test test")
print(matchStrings("foo bar", "bar baz"))
print(matchStrings("alpha beta", "beta gamma"))
in1 = "Okay, what about now? Looks like it sort of works. Key word being sort of."
in2 = "okay what about now looks like it sort of works key word being sort of looks"
bad_out = "Okay, what about now? Looks like it sort of works. Key word being sort of works key word being sort of looks"
good_out = "Okay what about now looks like it sort of works key word being sort of looks"
good_out = "Okay, what about now? Looks like it sort of works. Key word being sort of looks"
print(matchStrings(in1, in2))
assert(matchStrings(in1, in2) == good_out)
in1 = "This repository can take"
in2 = "This repository contains the code for"
bad_out = "This repository can tode for"
good_out = "This repository contains the code for"
assert(matchStrings(in1, in2) == good_out)
in1 = "See something."
in2 = "See something. Say something."
bad_out = in1
good_out = in2
print(matchStrings(in1, in2))
assert(matchStrings(in1, in2) == bad_out)
in1 = "a" * 1000
in2 = "b" * 10 * 1000
# This should be fast (< 1 second)
#matchStrings(in1, in2)
print("Tests passed.")
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